Handling interrupts (IRQ/XIRQ) - MC68HC

[Microcontroller_fan]

Previously i was created a different thread but it was not related to IRQ itself (i solved it by using a simple loop)
This is the hardest "suggested" exercise shown in this chapter (interrups for the 68hc11); i need a 68HC11 hero over here; i want to solve it from the beggining til the end; i tried so many times but i failed, this is a hard topic to me (i cannot move to the next section without understanding and solving this one,do you get me?)

It goes like this:


Who can help me with some assembly code?

 

[atferrari]

What is the actual meaning of "a pulse in one bit of memory location XXX must be generated"?

 

[Microcontroller_fan]

What is the actual meaning of "a pulse in one bit of memory location XXX must be generated"?

Hey pal, i think it means the pulse will change a bit (0 to 1 or 1 to 0) from memory location $0080.It states that the least significant bit corresponds to the SODA#1.
Have you got any idea about it?

 

[atferrari]

You say "the pulse". A pulse is something occurring in time and as far I understand it, is not asserting a particular bit in one register . Find that unclear.
Try to get a clarification.

 

[Microcontroller_fan]

You say "the pulse". A pulse is something occurring in time and as far I understand it, is not asserting a particular bit in one register . Find that unclear.
Try to get a clarification.

Oh, no.. it is not related to a "pulse clock" or something like that; in this particular example it means the "action". The mechanical seal will drop a soda and then, a "change" (action) has to be done in the memory location $0080. Is it clear for you?

 

[atferrari]

Oh, no.. it is not related to a "pulse clock" or something like that; in this particular example it means the "action". The mechanical seal will drop a soda and then, a "change" (action) has to be done in the memory location $0080. Is it clear for you?

Asserting a bit in memory is not a pulse.

 

[Pommie]

You mention "chapter", if this is a book I'd find a new one.

Mike.