Do you mean no integrated circuit regulator? If you are trying to get a constant 5.1V from a 6-9V supply then, by definition, you are creating a voltage regulator.no regulators
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Do you mean no integrated circuit regulator? If you are trying to get a constant 5.1V from a 6-9V supply then, by definition, you are creating a voltage regulator.no regulators
I'm not sure what you mean. It works with or without a load.@doug
i guess the circiut is only applicable when there is load
That's what the lower transistor is doing. As the current increases, that transistor starts to turn on which will reduce the drive to the upper transistor, thereby limiting the current. Feel free to simulate it.@ doug
**broken link removed** can limit the current in my circiut.. even i increase and increase the voltage?
Because you're connecting your voltmeter across the current sense resistor and not the points marked 'LOAD'why i get a mV as output?
According to my LTSpice sim it's just under 3V. Perhaps there are different Spice models out there?the LM317 seems to have a high overhead, that is it needs about 6 volts to work
I got 3.3V across the lm317 and 1.24V across R1 at the knee of IR2 for an overhead of 4.5596V for the current limiter set up, add to that 2V across R2 and you get the 6.5 volts I incorrectly referred to as overhead, good catch.According to my LTSpice sim it's just under 3V. Perhaps there are different Spice models out there?