For windmill project..

[pablome]

Ill have a dc motor that will generate voltage from the couple blades. What kind of battery should I use(preferably 12v) that will be coming from a charge controller.

 

[Jules_Theone]

What voltage do you have from the DC motor? How many amps? Which charge controller do you have?

Anyway, I would suggest lead-acid batteries because they are cheap, and can deal with punishment.

 

[pablome]

Jules_Theone -------------What voltage do you have from the DC motor? How many amps? Which charge controller do you have?

Anyway, I would suggest lead-acid batteries because they are cheap, and can deal with punishment. ---------------

DC motor is supposed to generate 12V DC. 1Amp..or thats after the inverter, 12Vac 1 amp. 50 W i think.

 

[Jules_Theone]

I don't understand -

12v x 1A = 12W

or

50W/12V = 4.1A


12Vac = 12v x 1.41* = 16.8Vdc

* (RMS)

13.8V is ideal for charging lead acid batteries, with the two diode drop from 16v it will be ok.

If you're using an inverter, that should have a battery low shut-down to stop the battery discharging too much, but it's also an idea to us a wind charger controller that can dump energy into a load when it's very windy or when the battery is fully charged.

I have a simple FET voltage clamp that dumps load into a high power resistor in a bucket of water when the voltage goes over 14v.

 

[pablome]

I don't understand -

12v x 1A = 12W

or

50W/12V = 4.1A


12Vac = 12v x 1.41* = 16.8Vdc

* (RMS)

13.8V is ideal for charging lead acid batteries, with the two diode drop from 16v it will be ok.

If you're using an inverter, that should have a battery low shut-down to stop the battery discharging too much, but it's also an idea to us a wind charger controller that can dump energy into a load when it's very windy or when the battery is fully charged.

I have a simple FET voltage clamp that dumps load into a high power resistor in a bucket of water when the voltage goes over 14v.

The 50W after the inverter, that makes more sense.

 

[Thunderchild]

The 50W after the inverter, that makes more sense.

the inverter won't create power only up your input voltage and loose you 10 % of the wattage in the process (90 % efficient inverter)