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Is it possible to charge it through usb?
... similar to manuals from a microwave telling you not to dry living animals in it.
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I used small heathink later but it is also hot! I think in such horrible heat the IC (7805) will die soon.
Should we have to calculate including dropout voltage for power dissipation of this IC? (like 7V for 7805, 11V for 7809 and so on?)
hi,
Its voltage across the 7805 times the current which gives the watts,
So if you have a 12Vdc input to a 7805 regulator passing 0.5A its 7V * 0.5A = 3.5Watts.
The 7805 will work with as little as 7.5V input, it requires at least 2.5V higher in the input than the output voltage.
If you have some power resistors you could drop say 4.5V at 0.5A across the resistor [ on the input side of the 7805]
So the power resistor would dissipate 4.5*0.5= 2.25watts [use a 5watt resistor] and the 7805 would dissipate 2.5v*0.5 = 1.25Watts.
It would still require the heat sink but would not get so hot.
E