You're missing the meaning of 'binary', the output can only be in one of two states, high or low - and as AG has pointed out, this will be the negative and positive supply rails.this is what I want to do.
at each change of state of the outputs in the binary counter 40193 a positive or negative pulse appears at the output of the schmitt trigger gate.
I took -6V + 6V as an example but I think I can also use -5V + 5V
it's true . you are right .In your circuit, the output of the Schmitt Trigger will never be at 0V, it will be +6V or -6V.
why -18 + 18?The Schmitt Trigger or a slower opamp will be destroyed by the +18V and -18V spikes produced by the capacitor.
Also the peaks of the pulses will be slanted, not square.
there is no frequency.What is the frequency of the signal?
How square do the pulses need to be?
that rail could include 0V, like when no power is applied, but a signal can be.Different gate families and ages have different levels of protection against this, but in lieu of specific information,the safe rule of thumb is don't exceed the rails by any amount, ever. Just plain don't.
Good point. What is wrong with this circuit:Isn't this the same question you were asking about in this thread?
Original thread started in 09 December. Four months later, we are no closer to a solution which will satisfy the OP.Isn't this the same question you were asking about in this thread?