Styx said:We have tried to help him in the past, but he will not help himself
To be quite honest I am surprised that the "regulars" have even bothered to put fingers to keyboard for him.
JimB
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Styx said:We have tried to help him in the past, but he will not help himself
walters said:Did i do the results right on the slope/rate of change formulas?
Slope= Rate of Change= V/time
:?: :?: :?:10V/10us= 1v/us
10V/5ms= 2v/ms
5v/ 60us= .0834v/us
5v/ 400us= .0125v/us
2v/ 40ms= .05v/ms
2v/ 40us= .05/us
5v/100ms= .05v/ms
It's the capacitor voltage that has the slope in this case.walters said:So a capacitor has a "Slope" when current goes through a capacitor?
This is correct, the resistor currents and voltages are independent of time, so their behavior is always controlled by Vresistor = I*R and Iresistor = V/Rwalters said:With current through a Resistor its just linear it just changes the voltage but doesn't change the "Time" or timing of the current or voltage?
For the first one, you use:walters said:2v/ 40us= .05/us
2v/ 40us * C .01uf = ?
5v/100ms= .05v/ms
5v/100ms * C .01uf = ?
differentiated" by the (dv/dt) term
dv/dt means we're differentiating with respect to time
The deravitive term is what causes the phase shift (mathmatically at least
"differentiate with respect to time," that means: (1) time is the independent variable (the x-axis), (2) voltage is the dependent variable (the y-axis), and (3) the derivative is the slope.
Well, not exactly. For AC sine waves, we always use "sin(x)" or "cos(x)" so we take the deriviates of those. For, the derivative of a 1KHz sine voltage would look like this...walters said:examples:
inputs a high frequency like 1K into a capacitor or inductor
the rate of change is a derivative
Now lower the frequency like 800hz into a capacitor or inductor the rate of change is Different derivative based on the inputs freq.