DC DC Boost Converter Implementation

[skyflyer54]

well what do you know...I was right

the other way is pick a frequency and duty cycle target.

calculate the primary inductance from 40% of 50KHz (8uS), 20V and the "inductor ripple" of 105A*0.3 = 31.5A:

Lp = TpVp/Ip = 8*20/31.5 = 5uH

now we have three other equations to work with:

Ls = TsVs/Is, Ls = LpT^2, and Is=Ip/T

If we plug the second two into the first and solve for T we get:

T = (TsVs)/(IpLp) = (12uS*325V)/(31.5A*5uH) = 24.76 = 25:1

Hi, U mean u have 2 winding side (pri and sec side) ? The inductor i'm using is only having one winding... What type of inductor are u using?

 

[Venkataiah Mekala]

please send me some informaion rearding dc-dc converter practical implementation

 

[Claude Abraham]

About 10 years ago, I used a diode-capacitor voltage multiplier inside the servo loop. It doubled the voltage, so that the pwm duty cycle needed was half. That is an option, as well as a transformer. The transformer turns ratio does some of the boosting requiring less pwm duty cycle. BR.