Sean,0RESET0 said:Len,
yes I have a multimeter. I am not sure what leads you are telling me to measure the voltage and current on. The TX uses one of the small 12v batteries. Probably like the one in your garage door opener.
P.S. I think I saw the number of combinations on the encoder/decoder represented as 3^8.
ljcox said:It is difficult to see the fine detail in the photo, but it gives me a general idea. So I've drawn the attachment to clarify.
Is there a number on the IC?
There are three numbers on the chip
PT2262 - 1SD38Z - KBCS6
The MFG is PTC
I don't understand what you mean by :-
"Measuring the voltage with 1H jumper-ed (A) gives me 8.5v at the start and then it drops to 7.6v the amps at the jumper are 3.5mA"
Do you mean that you measured the voltage with a jumper inserted between 1H & 1C?
What caused the voltage to drop to 7.6V?
Correct, I had a jumper connecting the two. It started dropping as soon as I measured the voltage. However, I just realized that I wasn't doing it right. I was measuring the voltage with the - probe on the spring and the + probe on the pins. I also didn't get a reading unless I hit the transmit button. So, Here are the readings done the correct way, no jumpers; bat + to L1 = 10.45v, 162mA; bat + to C1 = 8.85v, 2.6mA; to H1 = 9.25v, 0.9mA
I measured the resistance between the - spring and the pins with the battery out. L1 = 0.2 and the other two were open
You measured a current of 3.5 mA. Was this between 1H and the - battery with the jumper in or out?
In, See above.
You also said :- "Doing the same with 1L jumper-ed gives me 0.04v and 0.05mA"
So I assume you mean you measured the voltage and current at 1L with the jumper inserted between 1L and 1C.
How is the code set in the Rx?
It is set by soldering a connection between the pins of the IC and a puddle next to it, there are rows of puddles like the rows of pins on the Tx. I plan to add an eight position DIP switch to allow easy selection.
I suggest that you remove the jumper from row 1 and measure the voltage on 1L, 1C & 1H.
Does your Multimeter have a continuity setting?
If so, remove the battery, connect the Negative probe to the - battery spring and see if there is a connection to 1H, 1C and
1L. If it does not have the connectivity function, then use the lowest resistance setting and measure the resistances between these points.
Can you see the tracks on the other side of the PCB? If so, take a photo of it.
Which pins are connected to the IC? ie. the L row, the C row or the H row. I suspect it will be the C row.
I can't get a picture that is decipherable. It looks like the H row goes to pin 5 on the left side of the IC as seen in your drawing. All of the low pins are obviously connected but I think the connection to the circuit is on the other side of the board, covered by the pins. This PCB has traces on both sides.
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