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Gain of -25? If I input 1.5 Volts the output will be -37.5V ?
I wanted to know that if i connect a led to the output and slowly increase the input voltage from 0 to 5 (By using RC circuit), would the led sharply switch states or there would be intermediate states?
The CD4069 is a logic inverter. Stray feedback from output to input is negative feedback that simply reduces the high frequency gain and it will not oscillate.There is always the possibility of output oscillations around the midpoint of the input voltage due to stray feedback from the output to the input, which is amplified by the gate's gain that MikeML mentioned.
Not quite. A Schmitt trigger actually has a small amount of positive feedback which causes the output to abruptly change state at the switch point. This is no point where the output is at any voltage other then 0V or +5V.So, I think I quite got it. When Input is 1 Volts output is 5 volts. (as the datasheet says).
When input is 1.1 Volts the output is 5 - 25*0.1 = 2.5 Volts (as you said), and when input is 1.2 volts the output is 0 volts. Beyond this the amplifier has already saturated so the output remains 0 volts.
So, the state switching occurs at about 1.2 volts when increasing voltage from 0 to 5.
But, when I decrease voltage from 5 to 0, the stage switching occurs at about 3.8 Volts (by following similar analysis).
If these are true, then isn't the input behaving like Schmitt input?
You are correct, of course. Forgot about it being an inverter.The CD4069 is a logic inverter. Stray feedback from output to input is negative feedback that simply reduces the high frequency gain and it will not oscillate.