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Yea right. Vbe ≈ 0.6V aprox. And Vbe on both transistors is coupled in series. That means any supply voltage above ≈1.2V will short through emitter-base on each couple of transistors.It should work fine as long as all maximum ratings are not exceeded.
Yea right. Vbe ≈ 0.6V aprox. And Vbe on both transistors is coupled in series. That means any supply voltage above ≈1.2V will short through emitter-base on each couple of transistors.
Adding resistors between the bases of a pair of complementary transistors (Q3 - Q4) will not solve the problem. The transistors will connduct all the time (draw lot of current, but not shorting).
Not true! Adding a pair of resistors between the bases of each pair of transistors and feeding the control current at the junctions of the reisitors solves the OP's circuit's issues.
We don't know how much power the motors will dissipate, so the transistors doesn't have to burn.Yes, where as Grossel's version runs the transistors in a linear mode, losing loads of voltage for the motors, and overheating the transistors.
We don't know how much power the motors will dissipate, so the transistors doesn't have to burn.
Now I have posted two versions with their strength and weakness. In the first one, as Nigel stated, quite a bit power is lost due to the 1,2V loss over transistors
Nice, but yet so simple. To bad I'm not capable to think out good ideas on my ownHere's a working design from a kit robot on another of my sites.
Nice, but yet so simple. To bad I'm not capable to think out good ideas on my own
100€ question: What happens if both inputs goes high? Shortcut.
Nice, but yet so simple. To bad I'm not capable to think out good ideas on my own
100€ question: What happens if both inputs goes high? Shortcut.
And you shall share your ideas, wouldn't you?. . . . Soon, I'll get getting great ideas and won't even know why