Its Watts = V * I, I^2 * R, = 17^2 * 0.005 = 1.445WI have a shunt resistor - 5mOhm, 3W rating, 1% tolerance- and I pass through it up to 17Arms current, meaning it consumes ~1.5W.
It gets very hot when 17Arms flows in it.
If i chose a same shunt but with 5W rating, will it help conducting the heat?
Heatsink can be an aluminium plate, with 5mR bolted firmly to it, to carry away the heat.Thank you for you comments.
I must stick with the 5mOhm value.
what do you mean by attaching a heatsink to that?
What is a heatsink?
It gets so hot that you cant touch it for more than a split of a second.
Thank you.Heatsink can be an aluminium plate, with 5mR bolted firmly to it, to carry away the heat.
Then it's over 71C; if it boils water it's over 100C.It gets so hot that you cant touch it for more than a split of a second.
When you fit a power resistor to a pcb, its a good idea to mount the resistor above the pcb surface, leaving a gap for cooling air.I'm not sure that i understood your idea.
How a transistor can be used for heatsinking?
Moreover, its an air-shunt, so how can you sink the heat that its body absorbs, if its body is high above?