T tonald New Member Dec 19, 2009 #1 I have no idea about how to use the two "enable inputs". (the second part of the question) Thx Attachments ??.JPG 35 KB · Views: 346 Last edited: Dec 19, 2009
H Hayato Member Dec 20, 2009 #2 You gonna design a decoder that is only going to work when E0 and E1 are active.
H Hayato Member Dec 20, 2009 #4 A 3 to 8 decoder is a 3 to 2^3. You enter with 3 bits and it gives you 8 outputs. He wants a 13 to 2^13 decoder. You enter with 13 bits and it gives you 8192 outputs. You can reach that with some 3 to 8 decoders.
A 3 to 8 decoder is a 3 to 2^3. You enter with 3 bits and it gives you 8 outputs. He wants a 13 to 2^13 decoder. You enter with 13 bits and it gives you 8192 outputs. You can reach that with some 3 to 8 decoders.
H Hayato Member Dec 20, 2009 #5 For example, 2x 3-8 decoders allows you to build a 4 - 16 decoder. 4x 3-8 decoders, allows you yo build a 5 - 32 decoder. 8x 3-8 decoders, allows you to build a 6-64 decoder, and so on. 2 decods. = 4 bits input. 4 decods. = 5 bits input. 8 decods. = 6 bits input. 16 decods. = 7 bits input. You have a sequence there. For 13 bits input you need 1024 decoders.
For example, 2x 3-8 decoders allows you to build a 4 - 16 decoder. 4x 3-8 decoders, allows you yo build a 5 - 32 decoder. 8x 3-8 decoders, allows you to build a 6-64 decoder, and so on. 2 decods. = 4 bits input. 4 decods. = 5 bits input. 8 decods. = 6 bits input. 16 decods. = 7 bits input. You have a sequence there. For 13 bits input you need 1024 decoders.