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Comment 1: "Different base-emitter voltage"? A transistor does not "have" such a voltage. The base-emitter voltage Vbe is applied externally - and it has a certain relationship to the emitter resp. collector current as defined by the well known exponential formula (which, however, is remarkably temperature sensitive).The first thing I was taught about biasing a transistor is to never simply use one base resistor to a supply voltage.
Because each transistor has a different current gain and has a different base-emitter voltage even if they have the same part number.
Also, the current gain increases as the transistor heats up.
Therefore a voltage divider biases the base plus an emitter resistor is added to 0V.
Sometimes a biasing resistor is connecting between the collector and base for negative feedback.
Yes, although the input impedance is likely dominated by the low Rbe of a grounded-emitter amp (in the neighborhood of a few kΩ, depending upon the emitter current).There is one disadvantage of the shown bias scheme if compared with the Re method (emitter resistor):
The input resistance is reduced (Miller effect)