Yes, it's definitely a 64k static RAM. If as Nigel suggested you want to use it in your Z80 project, I would suggest buying 2 x 62256 to get the 64k required. You should be able to get them for a couple of dollars each. You would probably be better making one of them a 27256 EPROM.
Yes, it's definitely a 64k static RAM. If as Nigel suggested you want to use it in your Z80 project, I would suggest buying 2 x 62256 to get the 64k required.
Bit misleading?, 64K isn't 'required' it's the maximum addressable memory space - 8K would be plenty for learning about Z80. If I recall correctly, the complete circuit diagram I posted for him (EZ80 board) only used 2K?.
Bit misleading?, 64K isn't 'required' it's the maximum addressable memory space - 8K would be plenty for learning about Z80. If I recall correctly, the complete circuit diagram I posted for him (EZ80 board) only used 2K?.
If your going to go to the trouble of building this thing then you may as well put 32k of ROM and 32k of RAM. Especially when the total cost is around $5!!
Yes, although I think it makes far more sense to consider it an 8k one, as you don't use bits of memory, you use bytes - you could use 8 of those to give you a full 64K on your Z80!
Oh, i see. It is 64kbits, but 8kbytes. My bad. Thanks.
I already have a 32k SRAM and a 32k EEPROM for my z80. I was just wondering how big this one was. Actually, i found another one just like this one, so now i have 2 of the 8k SRAM chips
Yeah, I just noticed that last year. I was sitting at my PC and looked at my wireless router and it was like Mbps. I was thinking no way this router can transfer that many megabytes per second. Marketing I guess, advertise the larger number (ie. megabits).
I don't know about Linux but Windows measures disk space in KiB, MiB and GiB even though it incorrectly calls them KB, MB and GB.
Awhile ago some people decided to take a hard drive company to court for misselling them smaller hard drives. The court found in the hard drive company's favour because they used the correct terminology and the people were wrong.
Hi, about bits and bytes IBM 360 and 370 architecture used 1 byte = (8 bits) 2 bytes = 1 halfword (16 bits). 2 halfwords = 1 word (32bits). 2 words = 1 doubleword (64 bits) an 2 doublewords = 1 Quadword (128bits). see attachments for CNOP alignment and Machine format instruction formats.
Sorry to introduce another term (halfword)
Cheers RH
I don't know about Linux be Windows uses KiB, MiB and GiB even thought is calls them KB, MB and GB. The file I've attached is exactly 2000 bytes or 2KB long. Windows says it's 1.95KB, even though it really means 1.95KiB. I don't know about Linux as I'm in Windows mode at the moment and haven't looked at it under Linux yet.