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Ther is no voltage connected to the baseI can see you have a +10 & a -10 volt supplies. I can not see what voltage the Base is connected to.
Thanks for helpSince the base of the transistor is not used then the transistor is turned off and the currents are zero.
It is a homewor and this transistor is just a one question of itusing the drawing as shown:
Ie=0
Ib=0
Ic=0
Vbe=0
Vce=-20V
was this a "bonus" question on a test? i've seen quite a few in my time. i've used some of my own when asked to make a tech test for companies i've worked for. always good to see if the person is paying attention. such as putting a 7400 gate in a drawing with a 5.0V supply, and a 470 ohm pullup to 50V on one of the inputs, and the question " what does this circuit do?" answer i'm looking for: "smokes", "burns", or anything to that effect (it's a WAS gate).
And What if the base is connected to theI want to calculate the (IE, IB, IC, VBE, VCE) for the following transistor can any one help me
i have β=100
Thank you for this valuable information. This circuit is part of my homework and I could not solve it, becuse they did not connect the base to any source of voltage. When I asked my teacher, he told me that the base is connected to the positive voltage.can you help my to solve the questionHi,
I dont know what level of detail you are looking for here, but in some problems when the base is open then the collector base current becomes a deciding factor on what the transistor is doing. The collector base leakage is always present, but you would have to look at the data sheet and temperature to determine if the current is turning on the transistor a little. To compensate for this, most transistor circuits have a resistor from emitter to base so that this leakage current is swamped out. With the resistor, the leakage current is not high enough to reach the turn on threshold voltage of the base emitter.
If the base is connected directly to +10v in this circuit, then all the leakage current is forced into the +10v supply line and the transistor would be considered completely 'off' in most cases.
This could be an exercise to show the difference between having an open base and a base that is connected so as to shunt all leakage current bypassing the emitter base.
Look up the data sheet, then decide what you think about the leakage current specification. If you dont have a part number, trying using a common PNP transistor part number.
Same answer(s) as not connected. because there is no base current in both options.he told me that the base is connected to the positive voltage.can you help my to solve the question
now i think i found the anwesr .thank you all fore helping meSame answer(s) as not connected. because there is no base current in both options.
Same answer(s) as not connected. because there is no base current in both options.
i dont need that much of detils in my study the transistor in this case is off and we ignor the verey small currents .and happy new for you tooHi,
Sorry to disagree just a little but the collector base leakage current can turn the transistor slightly on. That's a known problem in some circuits so a base emitter resistor is used to swamp out any small current. It changes with temperature too. Check out a data sheet on one of the common transistors you know about.
And dont forget to have a Happy New Year
i dont need that much of detils in my study the transistor in this case is off and we ignor the verey small currents .and happy new for you too
Thank you for this valuable information. This circuit is part of my homework and I could not solve it, becuse they did not connect the base to any source of voltage. When I asked my teacher, he told me that the base is connected to the positive voltage.can you help my to solve the question