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If my understanding of JimB's circuit is correct then I would consider the 0 volt rail as earth. The 9 volt battery connects to the OP amp + and - power pins. (It does not connect to the 0 volt rail.) The 4.7 volt zenner makes the negative of the 9 volt battery sit at -4.7 volts an the + of the battery +4.3 volts. (With respect to the 0 volt rail.) The 9 volt battery only supplies the OP amp and the base drive current to the transistor. (Via the OP amp output pin.) The negative of the 3 volt battery will connect to the 0 volt rail. This battery will supply the output current. I suspect the transistor may need to be a darlington transistor unless the OP amp can supply enough base drive for an normal transistor. If you consider the 150 ohm resistor a fixed resistor and connect the - input of the OP amp the the junction of the 150 ohm resistor and the 1K resistor then the output should be almost exactly 0.7 volts.