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acquisition time in oscilloscope

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PG1995

Active Member
Hi,

Please have a look at the attachment.

It says that the acquisition time is 5 ms and to me it means that it takes 5 ms to finish the processing of a sample. In one second only 200 samples could be handled.

Sampling rate is 2 Million samples per second. Record length is 1 Million samples. The intake of samples is 2 Million per second and Record length (i.e. memory) is 1 Million samples and outgoing samples are only 200 then how come the memory of 1 Million samples is enough. Where am I going wrong with this? Please guide me. Thanks.
 

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PG1995

Active Member
Thanks.

But when I said "200" I was referring to "5 ms" acquisition time for a sample. 200 = 1/5*10^-3.

says that the acquisition time is 5 ms and to me it means that it takes 5 ms to finish the processing of a sample. In one second only 200 samples could be handled.[/unquote]
 

dknguyen

Well-Known Member
Most Helpful Member
I'm having trouble figuring out what you're confused about. Let me ask you this question, how long do you think the record length is IN TIME (not in samples)?
 

rjenkinsgb

Well-Known Member
Most Helpful Member
It says the acquisition time is = record length / sample rate.

The 5mS states is an example based on other example values and not a fixed time.
At 200 Million samples per second and using 1 MByte sample memory, the full memory represents a 5mS section of the waveform.

The "acquisition time" is the total duration of samples is can store at whatever sample rate is in use, for a given memory size.
If you were sampling at 100KHz with 1 MByte sample memory, the acquisition time would be ten seconds; that's the time taken to fill the display buffer.
 
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