acquisition time in oscilloscope

[PG1995]

Hi,

Please have a look at the attachment.

It says that the acquisition time is 5 ms and to me it means that it takes 5 ms to finish the processing of a sample. In one second only 200 samples could be handled.

Sampling rate is 2 Million samples per second. Record length is 1 Million samples. The intake of samples is 2 Million per second and Record length (i.e. memory) is 1 Million samples and outgoing samples are only 200 then how come the memory of 1 Million samples is enough. Where am I going wrong with this? Please guide me. Thanks.

 

[dknguyen]

Not 200 samples. It's 200 Msamples = 200 megasamples

 

[PG1995]

Thanks.

But when I said "200" I was referring to "5 ms" acquisition time for a sample. 200 = 1/5*10^-3.

says that the acquisition time is 5 ms and to me it means that it takes 5 ms to finish the processing of a sample. In one second only 200 samples could be handled.[/unquote]

 

[dknguyen]

I'm having trouble figuring out what you're confused about. Let me ask you this question, how long do you think the record length is IN TIME (not in samples)?

 

[rjenkinsgb]

It says the acquisition time is = record length / sample rate.

The 5mS states is an example based on other example values and not a fixed time.
At 200 Million samples per second and using 1 MByte sample memory, the full memory represents a 5mS section of the waveform.

The "acquisition time" is the total duration of samples is can store at whatever sample rate is in use, for a given memory size.
If you were sampling at 100KHz with 1 MByte sample memory, the acquisition time would be ten seconds; that's the time taken to fill the display buffer.