Hey all i am just wondering if my drawing below is correct in order to have an arduino detect an on or off led on another board using a optocoupler?
My thoughts of the above drawing is that when the led is on it will trigger the relay inside and send 5v to the arduino digital pin to read. 0v if the relay inside is not connected.
I also would possibly need to tell the arduino digital pin that its an input pullup like this:
It might work if you use the Opto coupler's transistor to pull the Arduino's input pin to ground. If the opto is off, the internal pull-up in the Arduino pulls the input pin high. If the opto is on, it sinks current, and pulls the input pin low.
If you connect your opto directly across the blue LED (Vf ≈3.3V) it will hog all the current and the blue LED will never light. If that is ok then do it that way. If not then connect the opto in series with a resistor between PIO1 and Gnd. Check data sheets for current available on PIO1 and needed by opto.
if you current mirro your led ? perhaps by some ratio to opto input ... would be quite fast (i assume)
your source by https://www.google.ee/
◄click to follow
to get - the image applies to https://www.vishay.com/docs/81864/4n25x000.pdf -- ****
then it takes to check the https://www.farnell.com/datasheets/2047068.pdf
to see that the company uses to mark the product from the same family so thet the text is oriented from least / highest pin no. toward the middle ones ...
so it takes one to two test to tell which is the case with 4N25
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note **** the datasheet shows characteristic graphs starting from 100µA iR-Led (Transmitter) current (IFW at legends) which has proven to be the case and in practice for xx817xx -s
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with uno