ThermalRunaway
New Member
Alright guys (and girls?)
I'm designing an audio spectrum analyser. It'll be a very crude design, with a function no more important than displaying it's output on a set of LEDs to represent low frequency to high frequency so that they "dance" in response to music. Not a new idea I know, and yes I know there'll already be circuits out there for this but I'm not after that I want to do the design work myself.
So anyway I'm currently looking into some 2nd order filters to see if the pass band will be narrow enough for what I want. I've got a very mathematical book in front of me and it's describing the operation of a 2nd order butterworth filter in terms of the following transfer function;
F(S) = Ho/Bn(S), where Ho is the d.c. gain and Bn(S) is the polynomial for the nth order filter.
I don't care where the equation comes from or how it's derived, I only care how I can use it. My question is, what does the (S) in brackets represent?
AudioGuru??
Brian
I'm designing an audio spectrum analyser. It'll be a very crude design, with a function no more important than displaying it's output on a set of LEDs to represent low frequency to high frequency so that they "dance" in response to music. Not a new idea I know, and yes I know there'll already be circuits out there for this but I'm not after that I want to do the design work myself.
So anyway I'm currently looking into some 2nd order filters to see if the pass band will be narrow enough for what I want. I've got a very mathematical book in front of me and it's describing the operation of a 2nd order butterworth filter in terms of the following transfer function;
F(S) = Ho/Bn(S), where Ho is the d.c. gain and Bn(S) is the polynomial for the nth order filter.
I don't care where the equation comes from or how it's derived, I only care how I can use it. My question is, what does the (S) in brackets represent?
AudioGuru??
Brian