SOLVE THIS!!!!!!!

[spec]

Hi Spec,
Your equation gives the correct value for the internal resistance of the cell .
ri = ( [I1*1]-[I2*4])/ (I2-I1). gives the correct answer.
= (1.2 * 1)- (0.4 *4)/(0.4-1.2)
= 1.2-1.6/-0.8
= -0.4/-0.8
= 0.5

Les.

Yeh, thanks Les.

 

[spec]

If you are willing to accept negative resistance, then your currents can be anything you want. Otherwise, you cannot expect to have more current after increasing the resistance.

Ratch

Of course,
But I just wanted to establish it mathematically

 

[JoeJester]

Well it works out for a wet cell that is almost discharged.

You can use 900 ma and 300 ma where the battery would be common to some dry cell batteries.

 

[spec]

Well it works out for a wet cell that is almost discharged.

You can use 900 ma and 300 ma where the battery would be common to some dry cell batteries.

Interesting

 

[tech master 117]

les jones is right.keep up really liked your answer and sorry that i didn't specify that ammeter has no resistance.now it is very easy to find out EMF do it guys.

 

[Les Jones]

Hi tech master 117,
John (jpanhalt) solved the problem before I did so he deserves the credit.

Les.