Matrix Problem

[tuck]

Hi all,
I having a problem on solving a matrix problem.
the equation is attached.
can anyone show me the step to get the answer for it?
Thanks.

 

[JMooney5115]

I'll give it a shot.

[0 1] is a 1x2 matrix and [0 10; 10 -1.8] is a 2x2 matrix. Multiplying these together would result in a 1x2 matrix of [10 -1.8]. Multiplying that matrix by the last one would result again in a matrix of 1x2. Which is [-1078.338 364.982] I have it worked out, just waiting for my scanner to start working.

Mooney

Will post pic in <5 minutes.

 

[JMooney5115]

I have pictures of my work. They are a little hard to read because the scanner at my college is not too good.

There are three pictures of my work. All different formats. Maybe you can read one of them.

jmooney5115 . google pages . com / matrix

Hope this helps.

Mooney

P.S. I checked it in matlab.

 

[Papabravo]

Did you notice the little -1 on the second matrix? It means "take the inverse". Anyway here is what I got using scilab.

-->A = [0 1]
 A  =

    0.    1.

-->B = [0 10; 10 -1.8
-->]
 B  =

    0.     10.
    10.  - 1.8

-->C = [1.5 44.51;607.41 44.51]
 C  =

    1.5       44.51
    607.41    44.51

-->B = inv(B)
 B  =

    0.018    0.1
    0.1      0.

-->A*B*C
 ans  =

    0.15    4.451

 

[MrAl]

Hi,


Same answer i get, and yes that little 'inversion' sign (-1) is hard
to see because it's so much smaller than the other text.

Using the notation:

[[a11,a12],[a21,a22]]=
| a11 a12 |
| a21 a22 |

Taking the inverse of B:

B'=B^(-1)= [[0.018,0.1],[0.1,0]]

D=A*B'=[0.1,0]

D*C=[0.15,4.451]

 

[JMooney5115]

Ah, I see the inverse sign now. My bad; tried to do it in a hurry and over looked it. Good thing someone else replied.

Mooney

 

[tuck]

Thanks for all the reply.
Is the invearse matrix is adjoints/Determinant ?

 

[tuck]

ok, I got it.
Thanks for all the help.