Hello.
I'd like to use a 8051 microcontroller from TI, and it says in its datasheet that:
"All digital pins have the internal pull-up resistor enabled during reset".
This doesnt happen in the current 8051 microcontroller I'm using, and I'm afraid it might cause me a problem.
Currently, there are 2 digital pins that are configured as outputs, and they drive a MOSFET-based H-bridge (the H-bridge has 2 inputs which are the 2 digital pins - the 2 digital pins drive the gates of the 4 MOSFETS).
The design of the H-bridge says that the two inputs must not be 1-Logic at the same time, since it will short the VDD to ground (through the Source-Drain conducting channels).
If I use now the new 8051 microcontroller, will the VDD be shorted to ground every time a reset occurs?
Meaning, I cannot use that 8051 microcontroller? (any way to overcome it?)
Thank you very much.
I'd like to use a 8051 microcontroller from TI, and it says in its datasheet that:
"All digital pins have the internal pull-up resistor enabled during reset".
This doesnt happen in the current 8051 microcontroller I'm using, and I'm afraid it might cause me a problem.
Currently, there are 2 digital pins that are configured as outputs, and they drive a MOSFET-based H-bridge (the H-bridge has 2 inputs which are the 2 digital pins - the 2 digital pins drive the gates of the 4 MOSFETS).
The design of the H-bridge says that the two inputs must not be 1-Logic at the same time, since it will short the VDD to ground (through the Source-Drain conducting channels).
If I use now the new 8051 microcontroller, will the VDD be shorted to ground every time a reset occurs?
Meaning, I cannot use that 8051 microcontroller? (any way to overcome it?)
Thank you very much.
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