How does one calculate the voltage droop when a load is placed on a voltage divider circuit?
I have wired up a 12v supply with two 1k resistors in series, to give 6v output inbetween the resistors. But when I place a 6v motor in parallel with the second resistor the voltage droops dramatically.
The motor itself has an 8ohm resistance. Do I have to calculate for that resistance when creating the voltage divider circuit?
I have wired up a 12v supply with two 1k resistors in series, to give 6v output inbetween the resistors. But when I place a 6v motor in parallel with the second resistor the voltage droops dramatically.
The motor itself has an 8ohm resistance. Do I have to calculate for that resistance when creating the voltage divider circuit?