The 100,000 V can be lowered to 20,000 V by using two resistors in a voltage divider circuit (in series).
Example :
(+)100,000------------------------/\/\/\/\/------------------A-----------------/\/\/\/\/----------------------(-)
For the current to flow above to be 5mA; 100,000 divided by 0.005A = 20MΩ
The sum of resistance-left plus resistance-right is to be 20MΩ
For the point A to be 20,000V, that would be the voltage across resistor right.
The resistance-right value is then 20,000 divided by 0.005 A = 4MΩ
The resistance-left value is then 80,000 divided by 0.005 A = 16MΩ
All calculations use Ohm's law.
So, the voltage at point A is now only 20,000 from a source of 100,000 V
-If that is what you asked-