I asked you specifically about the control voltage in a previous post:
I don't think you understand my question. Where does your input voltage come from? When the input voltage gets clamped, it doesn't go away, like the charge on the cap does when it gets discharged. The input voltage is still there - it is just "disconnected" from the input. If you release the input clamp as soon as the cap discharges, the cap will start to charge again. Then you have an oscillator, as we have discussed. If, on the other hand, you latch the input clamp, you will need some sort of external stimulus to reset the clamp.
I think the key point I'm trying to make is that the input voltage is (in my mind) an independent control voltage. If it goes to zero when you clamp it, how does it assume a non-zero value some finite length of time later?
Cutting off the current is equivalent to resetting the input voltage. It's what you do next that's critical.
In the last schematic, I reset the flip-flop when the ramp got to zero, because you gave me either that option or the option of using a one-shot.
A third option is the external reset (some sort of pulse input, or a switch) to reset the flip-flop, as I mentioned above. See the circuit below.
We could instead cut off the current by resetting the input voltage, but it would require an analog switch (two, to do it right), and we would wind up with the same functionality.
Speaking of functionality, I asked you several times about the usefulness of this, but you seemed to think your instructor would be dazzled by the rope tricks - never mind that we couldn't catch a steer with them.
PS V5 is still your control voltage. I just used a battery for the sim.