- Given that opposition to current flow is known as resistance
- If I have a series circuit with a 12 volt source and 2 resisters, R1 & R2 at 2Ω and 4Ω respectively
- I will measure 2 amps at any point in the circuit
- Why are the resisters, which oppose current flow, not reducing the current individually?
- Is the voltage drop across each resister the force "consumed" (my word) by the resistor as the "force" tries to push a constant amount of electrons (2 amps in this case) against the resistance?
- If that were the case why wouldn't I measure 8 volts at the far side of R1 (E=2amps X 2Ω= 4 volts = voltage drop at R1)?
- If I did measure 8 volts after R1 why wouldn't I use that value to calculate the voltage drop at R2 instead of the applied voltage of 12 volts?
This stuff is really confusing. I'm sure I'm missing something obvious.
- If I have a series circuit with a 12 volt source and 2 resisters, R1 & R2 at 2Ω and 4Ω respectively
- I will measure 2 amps at any point in the circuit
- Why are the resisters, which oppose current flow, not reducing the current individually?
- Is the voltage drop across each resister the force "consumed" (my word) by the resistor as the "force" tries to push a constant amount of electrons (2 amps in this case) against the resistance?
- If that were the case why wouldn't I measure 8 volts at the far side of R1 (E=2amps X 2Ω= 4 volts = voltage drop at R1)?
- If I did measure 8 volts after R1 why wouldn't I use that value to calculate the voltage drop at R2 instead of the applied voltage of 12 volts?
This stuff is really confusing. I'm sure I'm missing something obvious.
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