I found it more comfortable to deal with the change in conductance or resistance as the depth increases, and many other web sites quote the same.
To paraphrase a few:
"The skin effect causes the effective resistance of the conductor to increase at higher frequencies where the skin depth is smaller, thus reducing the effective cross-section of the conductor."
"Frequency dependence of resistance:
Another complication of AC circuits is that the resistance and conductance can be frequency-dependent. One reason, mentioned above is the skin effect."
Resistance and conductance are not the same thing as resistivity and conductivity. Resistivity and conductivity are intrinsic properties of the copper. Resistance and conductance (of a piece of wire, for example) are the result of taking into account the geometry of a piece of copper and where the connections to it are made.
The resistance of a piece of wire at DC is given by R = rho*L/A, where rho is the resistivity, L is the length of the piece of wire, and A is the cross sectional area of the wire. At AC the resistance is different due to skin effect causing the current density to vary across the cross section of the wire, not rho. rho is the same everywhere in the copper at DC and AC frequencies below gigahertz frequencies, which is the region we're discussing.
In an earlier post you said:
Hi,
If we look at the effect along the radius of a long wire the current density changes as an exponential. Integrating over the radius using this exponential as a weighing function provides us with the following formula:
r=2(g^2*(e^(-1/g)-1)+g)
where
g=1361/(6641*pi*sqrt(f)*R)
for copper wire, and
f is the frequency in Hertz and R is the radius of the conductor in meters,
and r is the ratio of DC resistance to AC resistance, so an r value of 0.5 for example means the AC resistance is 2 times higher than the DC resistance.
This formula is not like the formula where we assume that the penetration depth is only equal to the skin depth, and obtain the AC resistance from that. That formula is limited because the approximation falls short when the radius of the wire gets closer to the skin depth. For example, the approximation would give an estimate of close to 0.5555 for a wire with radius three times the skin depth, while the better approximation from the formula above yields an estimate closer to 0.4555.
The skin depth at 100kHz is 0.206mm, which is about equal to the radius of a #26 gauge wire, and using the older approximation this tells us that the AC resistance is about equal to the DC resistance. This is the largest wire size recommended by Magnetics Inc for use at 100kHz. They obviously used the single skin depth approximation to determine this, which isnt too bad really.
However, using the formula above, the DC to AC resistance ratio for an AWG #26 wire at 100kHz comes out close to 0.74, meaning the AC resistance is about 35 percent greater than the DC resistance. This tells us that #26 isnt that bad, but we can of course do better with a larger wire size.
You were using current density as the variable in your calculations; using current density is the thing to do. Current density does vary with depth in the wire, but resistivity does not.
However, your analysis of the case where the skin depth is close to the wire radius is flawed. You say that "If we look at the effect along the radius of a long wire the current density changes as an exponential." This is not close to the truth when the skin depth is near the radius. The exact expression for the current density variation with depth in a round cylindrical wire involves Bessel functions, and is not well approximated by using an exponential when skin depth is nearly the same as the radius.
When the skin depth is very small compared to the radius, then using the exponential is a good approximation. This is discussed in Ramo, Whinnery and Van Duzer. An exact solution to the problem in Bessel functions exists. Also, Terman has a graph showing Rac/Rdc for various ratios of skin depth to radius.
If we take the radius of a 26 ga wire as .202 mm, the exact value of Rac/Rdc at 100 kHz is 1.0179. The expression g=1361/(6641*pi*sqrt(f)*R) gives 1.0212, quite close to the exact value. Your adjustment formula, r=2(g^2*(e^(-1/g)-1)+g), overestimates the value as 1.35
Taking the radius of 22 ga wire as .322 mm, the exact formula gives Rac/Rdc as 1.10745. Your formula gives 1.59.
I cut off a 3 foot piece of 22 ga magnet wire and measured the AC resistance versus frequency with an impedance analyzer:
The B marker indicates a resistance at 100 kHz of 52.531 milliohms, and the A marker at 1 kHz shows 48.271 milliohms, for an Rac/Rdc ratio of 1.088, which is fairly close to the exact value of 1.107, and not so close to your formula's value of 1.59
Apparently your technique of viewing resistivity as something that varies with depth doesn't work:
Well, the point i was making was, so is cross sectional area, The area is a well defined measurement yet traditionally no one has a problem with redefining the area to account for a change in properties even though it will not be the actual measured area anymore.
We can call it the AC resistivity then, if you feel more comfortable with that. Otherwise i'd have to change the formula to show the apparent (not real) change in area which would make it look like we were squeezing the wire from all radial directions

In any case though, the final result would come out the same.