ericgibbs Well-Known Member Most Helpful Member Sep 22, 2010 #2 Transistorman said: anyone know a simple way ? Click to expand... hi TT, This question is very ambiguous, what do you mean....
Transistorman said: anyone know a simple way ? Click to expand... hi TT, This question is very ambiguous, what do you mean....
MikeMl Well-Known Member Most Helpful Member Sep 22, 2010 #3 Transistorman said: anyone know a simple way ? Click to expand... How about a cheap way?
Transistorman Member Sep 22, 2010 #4 ericgibbs said: hi TT, This question is very ambiguous, what do you mean.... Click to expand... im trying to make keypad using only one analog port i want to measure the analog input so i can put the right analog input to my code i will post my schematic after this post
ericgibbs said: hi TT, This question is very ambiguous, what do you mean.... Click to expand... im trying to make keypad using only one analog port i want to measure the analog input so i can put the right analog input to my code i will post my schematic after this post
ericgibbs Well-Known Member Most Helpful Member Sep 22, 2010 #7 Transistorman said: here is the schematic **broken link removed** Click to expand... hi TT, What do you think the voltage will be on pin 7 when you press either switch.???????? Last edited: Sep 22, 2010
Transistorman said: here is the schematic **broken link removed** Click to expand... hi TT, What do you think the voltage will be on pin 7 when you press either switch.????????
Nigel Goodwin Super Moderator Most Helpful Member Sep 22, 2010 #8 ericgibbs said: hi TT, What do you think the voltage will be on pin 7 when you press either switch.???????? Click to expand... Not to mention that the 12F629 doesn't have an ADC If he wants to use the 12F629?, then he could checkout my joystick tutorial, which would allow him to do what he wants.
ericgibbs said: hi TT, What do you think the voltage will be on pin 7 when you press either switch.???????? Click to expand... Not to mention that the 12F629 doesn't have an ADC If he wants to use the 12F629?, then he could checkout my joystick tutorial, which would allow him to do what he wants.
Transistorman Member Sep 22, 2010 #9 ericgibbs said: hi TT, What do you think the voltage will be on pin 7 when you press either switch.???????? Click to expand... i dont know
ericgibbs said: hi TT, What do you think the voltage will be on pin 7 when you press either switch.???????? Click to expand... i dont know
ericgibbs Well-Known Member Most Helpful Member Sep 22, 2010 #10 Transistorman said: i dont know Click to expand... hi TT, Use Ohms law. The input resistance of the analog is VERY high compared to the 1K and 10K resistors. Current = Voltage/Resistance..... the resistance is the sum of the 1K or 10K with very input resistance.......... So a little test for you, what do you think the current thru the 1K is if the adc input is say 1megohm.....???????
Transistorman said: i dont know Click to expand... hi TT, Use Ohms law. The input resistance of the analog is VERY high compared to the 1K and 10K resistors. Current = Voltage/Resistance..... the resistance is the sum of the 1K or 10K with very input resistance.......... So a little test for you, what do you think the current thru the 1K is if the adc input is say 1megohm.....???????
Nigel Goodwin Super Moderator Most Helpful Member Sep 22, 2010 #11 ericgibbs said: So a little test for you, what do you think the current thru the 1K is if the adc input is say 1megohm.....??????? Click to expand... And it's a LOT higher than that.
ericgibbs said: So a little test for you, what do you think the current thru the 1K is if the adc input is say 1megohm.....??????? Click to expand... And it's a LOT higher than that.
Transistorman Member Sep 22, 2010 #12 Nigel Goodwin said: Not to mention that the 12F629 doesn't have an ADC If he wants to use the 12F629?, then he could checkout my joystick tutorial, which would allow him to do what he wants. Click to expand... sorry , wrong pick i though it was 12F675 too hurry of making schematic besides of that i also have 627 to play with , right ?
Nigel Goodwin said: Not to mention that the 12F629 doesn't have an ADC If he wants to use the 12F629?, then he could checkout my joystick tutorial, which would allow him to do what he wants. Click to expand... sorry , wrong pick i though it was 12F675 too hurry of making schematic besides of that i also have 627 to play with , right ?
ericgibbs Well-Known Member Most Helpful Member Sep 22, 2010 #13 Nigel Goodwin said: And it's a LOT higher than that. Click to expand... hi Nigel I know that, but I am trying to make the sums easier to start with............... I dont think TT knows the basic Ohms methods..yet.
Nigel Goodwin said: And it's a LOT higher than that. Click to expand... hi Nigel I know that, but I am trying to make the sums easier to start with............... I dont think TT knows the basic Ohms methods..yet.
Transistorman Member Sep 22, 2010 #14 ericgibbs said: hi TT, Use Ohms law. The input resistance of the analog is VERY high compared to the 1K and 10K resistors. Current = Voltage/Resistance..... the resistance is the sum of the 1K or 10K with very input resistance.......... So a little test for you, what do you think the current thru the 1K is if the adc input is say 1megohm.....??????? Click to expand... i dont understand so there is a way to calculate analog input ?
ericgibbs said: hi TT, Use Ohms law. The input resistance of the analog is VERY high compared to the 1K and 10K resistors. Current = Voltage/Resistance..... the resistance is the sum of the 1K or 10K with very input resistance.......... So a little test for you, what do you think the current thru the 1K is if the adc input is say 1megohm.....??????? Click to expand... i dont understand so there is a way to calculate analog input ?
Nigel Goodwin Super Moderator Most Helpful Member Sep 22, 2010 #15 Transistorman said: i dont understand so there is a way to calculate analog input ? Click to expand... Look up 'potential divider'.
Transistorman said: i dont understand so there is a way to calculate analog input ? Click to expand... Look up 'potential divider'.
Transistorman Member Sep 22, 2010 #16 Nigel Goodwin said: Look up 'potential divider'. Click to expand... ok , i will take a look