hantto
Member
Hello!
I've made my own delay subroutine and naturally I want it to be as exact as possible. I use the call instruction to call a smaller delay to get a loger one. I read that the call instruction takes two instruction times to execute. So my question is does it take two instruction times when it jumps to the other place and two instruction times when it jumps back. OR only two instruction times for the whole thing?
Hrm, was that clear enough to understand?
I've made my own delay subroutine and naturally I want it to be as exact as possible. I use the call instruction to call a smaller delay to get a loger one. I read that the call instruction takes two instruction times to execute. So my question is does it take two instruction times when it jumps to the other place and two instruction times when it jumps back. OR only two instruction times for the whole thing?
Hrm, was that clear enough to understand?