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# need help in some basics

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#### djfaisal

##### New Member
Hello

Q: why the total ressitance in parallel circuits are less than the smallest resistor value? please explain with logical reason.

Regards

Because two paths will always pass more current than one.

Dear Brown

Could you please give me little explanation, of what you tell in the last relply.

Thanks

Just think about it. You add a path for conduction. Some of the electrons that were crowded in the original path will use the new one. It's like when you're waiting in the chekcout line at the market, and they open another register. Many of the customers who were waiting in the original line rush to the new one, and everyone goes through faster.

Great analogy!!!! I love mental pictures. I'll remember that one.

To BrownOut:

Another example is water faucets in your home.

If you take two 5 gallon buckets to your faucets (kitchen and bathroom) and open the valves, you will get 10 gallons much quicker than you would if you only opened the kitchen faucet and filled them both.

The two faucets are in parallel off of your water supply manifold in your home. Opening both faucets doubles the flow of water, thus your water resistance is AT LEAST HALF of what it is when only one faucet is open. If one valve has more flow by nature (like a bathtub), it also has the least resistance. So opening another valve (the kitchen sink) decreases the overall resistance to the point it is LESS than the bathtub resistance alone.

Does this help or make sense?

Because two paths will always pass more current than one.

Unless you have two 1kΩ paths compared to one 10Ω path, for example but I'm nitpicking, I knew what you meant

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