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shermaine said:Sorry about.....
Juz got a little puzzled over sloving this integration.......
Any one can help?
sin^2 + cos^2tdt
Pls advise...
shermaine said:Sorry.....
The integration is sin^2t + cos^2tsintdt
f(x) g(x)
f'(x) INT[g(x)]
f''(x) INT[INT[g(x)]]
...
0 INT[INT[...[g(x)]]]
f(x) +g(x)
f'(x) -INT[g(x)]
f''(x) +INT[INT[g(x)]]
...
0 -INT[INT[...[g(x)]]]