please help me with my project, Anyone who's familiar with this circuit, can you help me to know what watts is this resistor? the circuit is in the link below..
And can u help me to have the PCB design, I little unfamiliar with the connection of 3 feet of the transistor. How many transistor in this circuit?
Thanks!
please help me with my project, Anyone who's familiar with this circuit, can you help me to know what watts is this resistor? the circuit is in the link below..
And can u help me to have the PCB design, I little unfamiliar with the connection of 3 feet of the transistor. How many transistor in this circuit?
Thanks!
If you go online and search for expresspcb its a free schematic and pcb layout program.
Its very easy to use, do a layout and post it, we will guide you thru it.
You should not use that simple circuit with a 12V supply. The max allowed reverse voltage for the emitter-base junction of the BD679 darlington transistors is 5V but with a 12V supply they will try to reach 11V and cause avalanche breakdown which is bad. The high avalanche breakdown current might cause the capacitors to blow up.
Use a 6V supply or add diodes to stop the avalanche breakdown.
Ceramic capacitors probably will not blow up but their small value will result in a fairly high frequency. The emitter-base junctions of the transistors will still have avalanche breakdown which is bad for them.
I wouldn't bother with a etched PCB for a simple project like this. Get a prototyping PCB with pre-etched tracks that you can cut with an exacto knife.
Also add the diodes as mentioned by AG:
No, you want the (-) side of the cap to go below ground when it's associated transistor turns on. Placing the diodes the way you suggested would result in high currents through the diodes and caps.
The capacitor charges to 10V or 11V so use 16V or 25V capacitors.
Calculate the power in the resistors. It is only 0.03W so any small resistors will be fine.
I don't know why your circuit stopped working. Maybe the polarity of the capacitors is backwards or maybe you connected the pins on the transistors backwards.
Good point about the high capacitance current with parallel diodes. The attached design uses resistors to limit the discharge current. The diodes clamp the reverse voltage across the BE junction of the transistor to less than 1V.
The problem I have with series diodes is that significant reverse voltage can still exist in the transistor's base, depending on relative reverse recovery times, leakage currents, etc. My design, although not commonly used, accurately controls the reverse voltage ( green trace in the waveform window ) The tradeoff is the limiting resistor must be carefully chosen to sustain oscillations. R7 would not be used in the acutal circuit. It's only included to get oscillations started in the simulation.
The high wattage rating of the resistor will not affect the operation of your circuit. 1/8 watt would be more appropriate however.
It might not be working due to the filiment bulbe used in the transistor collectors. You probably can't just plug any old bulb in to this circuit. That's a big weakness in this design.
The power rating of resistors is related to their size.
If they are still 4700 ohms then the circuit will work if everything else is correct.
But as I explained before, the circuit is wrong because it is missing two diodes.
Without the diodes then if the supply is more than 6V the transistors are damaged.
Ceramic capacitors probably will not blow up but their small value will result in a fairly high frequency. The emitter-base junctions of the transistors will still have avalanche breakdown which is bad for them.