R ravi17 New Member Aug 1, 2017 #1 hi, the PCM1789 DAC specifies its output as two differential output with 8Vpp voltage output. Does it mean 8Vpp on each channel or 4Vpp on each channel? thank you!
hi, the PCM1789 DAC specifies its output as two differential output with 8Vpp voltage output. Does it mean 8Vpp on each channel or 4Vpp on each channel? thank you!
K kubeek Well-Known Member Most Helpful Member Aug 1, 2017 #3 Each output pin is 4Vpp, therefore their difference is 8Vpp in each channel.
ronsimpson Well-Known Member Most Helpful Member Aug 1, 2017 #4 The IC has a 0 to 5V power supply for the analog output. So a single output could not be more than 5Vp-p. Last edited: Aug 1, 2017
The IC has a 0 to 5V power supply for the analog output. So a single output could not be more than 5Vp-p.
R ravi17 New Member Aug 1, 2017 #5 it was on the datasheet, i didn't see before, it is 4Vpp on each channel
F flatfootskier Member Aug 1, 2017 #6 Also on the datasheet though Output voltage Differential 1.6 × VCC1 VPP 5 x 1.6 = 8 I'm confused. easily done though...
Also on the datasheet though Output voltage Differential 1.6 × VCC1 VPP 5 x 1.6 = 8 I'm confused. easily done though...
ronsimpson Well-Known Member Most Helpful Member Aug 1, 2017 #7 flatfootskier said: Differential Click to expand... Output1 - output2 = differential I don't really know but lets say the output is 0.5v to 4.5v which is 4vp-p. This is Vcc X 0.8. Output1 is 4.5v - Output2 is 0.5v = +4v Output1 is 0.4v - Output2 is 4.5v = -4v Differential is (+4 - -4v)=8V
flatfootskier said: Differential Click to expand... Output1 - output2 = differential I don't really know but lets say the output is 0.5v to 4.5v which is 4vp-p. This is Vcc X 0.8. Output1 is 4.5v - Output2 is 0.5v = +4v Output1 is 0.4v - Output2 is 4.5v = -4v Differential is (+4 - -4v)=8V