M Mdkanz New Member Mar 14, 2009 #1 Is there a formula to find the db per octave of a low pass filter like this one? R1 ------------------\/\/\/---------------------------- | | | --- --- C1 | | | ----------------------------------------------------
Is there a formula to find the db per octave of a low pass filter like this one? R1 ------------------\/\/\/---------------------------- | | | --- --- C1 | | | ----------------------------------------------------
audioguru Well-Known Member Most Helpful Member Mar 14, 2009 #3 Your extremely simple filter is backwards. The input is at the resistor on the right. The output is at the resistor and the capacitor on the left. Its slope is only 6dB/octave.
Your extremely simple filter is backwards. The input is at the resistor on the right. The output is at the resistor and the capacitor on the left. Its slope is only 6dB/octave.
Mikebits Well-Known Member Mar 14, 2009 #5 The calculations are given at this web site. **broken link removed**
K kchriste New Member Forum Supporter Mar 14, 2009 #6 Mdkanz said: I said that the C1 should be to the right of R1 Click to expand... The way to preserve the formatting is to use the code tags: Code: [FONT="Times New Roman"] R1 ------------------\/\/\/---------------------------- | | | --- --- C1 | | | ----------------------------------------------------[/FONT] Last edited: Mar 14, 2009
Mdkanz said: I said that the C1 should be to the right of R1 Click to expand... The way to preserve the formatting is to use the code tags: Code: [FONT="Times New Roman"] R1 ------------------\/\/\/---------------------------- | | | --- --- C1 | | | ----------------------------------------------------[/FONT]