You are treating LEDs as if they were incandescent light bulbs.
Light bulbs are resistive in nature. They only draw as much current as thy need.
LEDs are semiconductors. They are not resistive in nature. If you were to hook a 2V LED to a 2V voltage supply it would draw as much current as the source was able to supply. If the current is too much the LED burns out. Or you might harm the supply.
To overcome this we use a supply with a voltage that is greater then LED or LED string and use a resistor to limit the current.
Lets say you have a 11 volt supply. You could use 5 LEDs in series with a Vforward (drop) of 2 volts. The LEDs require 10V of our 11V. We will drop the last 1V using a resistor. The resistor also limits the current for the entire string of LEDs. Current limiting is very important.
To calculate the needed resistance we need to know both the voltage drop, in this case 1V, and the current we want to supply the LEDs with. The current is specified in the datasheet. In many common LEDs 20mA.
Use ohms law
Resistance= Volts/Current = 1V/.020A = 50Ohms
So you would use a 56Ohm resistor which is the nearest available value.
This site has a calculator to make you life easier.
LED Resistor Calculator
EDIT: I did not look at the transistors to see if you are using them properly.