N nabliat6 New Member Jan 19, 2010 #1 https://i48.tinypic.com/1o4ow9.jpg why in this circuit they say that in t<0 the voltage on both capacitators is 12 volts?? if both points of each capacitators is connected to the voltage source directy then 12 volts is ok. but here we have a resistor between them this resistor drops the original voltage it cannot be 12
https://i48.tinypic.com/1o4ow9.jpg why in this circuit they say that in t<0 the voltage on both capacitators is 12 volts?? if both points of each capacitators is connected to the voltage source directy then 12 volts is ok. but here we have a resistor between them this resistor drops the original voltage it cannot be 12
Grossel Well-Known Member Jan 19, 2010 #2 nabliat6 said: https://i48.tinypic.com/1o4ow9.jpgwhy in this circuit they say that in t<0 the voltage on both capacitators is 12 volts?? Click to expand... Because they assume that the caps is already charged when measurements starts. nabliat6 said: if both points of each capacitators is connected to the voltage source directy then 12 volts is ok. Click to expand... Yes. There will be no potential difference, and no current flow either. nabliat6 said: but here we have a resistor between them this resistor drops the original voltage it cannot be 12 Click to expand... With respect to ground, yes - that will measure 12V.
nabliat6 said: https://i48.tinypic.com/1o4ow9.jpgwhy in this circuit they say that in t<0 the voltage on both capacitators is 12 volts?? Click to expand... Because they assume that the caps is already charged when measurements starts. nabliat6 said: if both points of each capacitators is connected to the voltage source directy then 12 volts is ok. Click to expand... Yes. There will be no potential difference, and no current flow either. nabliat6 said: but here we have a resistor between them this resistor drops the original voltage it cannot be 12 Click to expand... With respect to ground, yes - that will measure 12V.