Inductor

P

Piyush Ramraika

New Member

• Oct 16, 2013

• #1

I want to make an inductor coil using coil but i am not getting the formula for the design and measuements. Can anyone help

 

MikeMl

Well-Known Member

Most Helpful Member

• Oct 16, 2013

• #2

What type of coil? wound on what? ferrite, iron, air

 

P

Piyush Ramraika

New Member

• Oct 16, 2013

• #3

MikeMl said:

What type of coil? wound on what? ferrite, iron, air

Click to expand...

Sir a have 24SWG coil and i am going to use air core

 

MikeMl

Well-Known Member

Most Helpful Member

• Oct 16, 2013

• #4

What is "24SWG"?

 

ericgibbs

Well-Known Member

Most Helpful Member

• Oct 17, 2013

• #5

MikeMl said:

What is "24SWG"?

Click to expand...

Morning Mike,
Its Imperial, Standard Wire Gauge, an olde Brit standard.
https://www.bulkwire.com/wiregauge.asp

Eric

 

Ian Rogers

User Extraordinaire

Forum Supporter

Most Helpful Member

• Oct 17, 2013

• #6

an olde Brit standard.

Click to expand...

Your even going older..

 

B

BobW

Active Member

• Oct 18, 2013

• #7

What inductance value are you looking for?
A single layer solenoid is easiest to calculate accurately, but if you need higher inductance values than what can be practically obtained from a single layer winding then there are some multi-layer formulae that are reasonably accurate. There is no single formula that is good for every geometric configuration.


BTW, according to this online calculator:
https://www.coilwindingmachines.eu/engineers_corner/awg_swg_converter.html
#24SWG = .559 mm which would be equivalent to #23.2 AWG

 

Last edited: Oct 18, 2013

jpanhalt

Well-Known Member

Most Helpful Member

• Oct 18, 2013

• #8

Here's a calculator: https://www.circuits.dk/calculator_multi_layer_aircore.htm

Here's a similar formula from a Tesla site: https://www.pupman.com/listarchives/1998/April/msg00062.html

Both appear to have empirical elements.

John