I have a basic circuit that has an inductor which has a resistance of 10Ω, it is connected to a 110v 50Hz supply that draws 8A.
I want to calculate the Inductance of the Coil but I seem to be having difficulty understanding if the Resistance of the coil has any bearing on the calculations.
I have attempted the Math below with an explanation of my dilema.
I first calculated XL
XL= V/I
XL= 110/8 = 13.8Ω
L = XL/2(pi)f
= 13.8/314
L = .044H
Now to verify, if I calculate 2(pi)fL to get XL I get
6.28 X 50 X .044
XL=13.8 Which corresponds to above.
My misunderstanding is that in the First equation XL= V/I.
Doesn't this give the Total Impedance Z @ 50Hz & not just the XL of the coil, it has the 10Ω resistance included giving ZT & not XL to be used in the equations to find L.
Are my equations correct to find L?
Cheers
I want to calculate the Inductance of the Coil but I seem to be having difficulty understanding if the Resistance of the coil has any bearing on the calculations.
I have attempted the Math below with an explanation of my dilema.
I first calculated XL
XL= V/I
XL= 110/8 = 13.8Ω
L = XL/2(pi)f
= 13.8/314
L = .044H
Now to verify, if I calculate 2(pi)fL to get XL I get
6.28 X 50 X .044
XL=13.8 Which corresponds to above.
My misunderstanding is that in the First equation XL= V/I.
Doesn't this give the Total Impedance Z @ 50Hz & not just the XL of the coil, it has the 10Ω resistance included giving ZT & not XL to be used in the equations to find L.
Are my equations correct to find L?
Cheers