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Identify resistor help please.

Nigel Goodwin

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Still don't see how a 1 M resistor can get so hot that it fries itself and scorches the board through to the bottom side. 1 W of heat in a 1/4 W body would take 1000 V RMS or DC.
Possibly the resistor has gone low in value, although they don't look the type that do? - historically it was a relatively common fault, with high voltage resistors going low in value, which makes them dissipate more power, which in turn makes them go lower still etc.
 

ronsimpson

Well-Known Member
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I drew out part of the circuit and I don't understand.
I thought the .47 & .56 caps are for 120/220 volts but now I think not.
Every cap is 400v. Why?
There is a part that looks like it is in backwards. What is written on the part? "13001"
Maybe the brunt resistor is 10 ohms as a load when the battery is not charging. ??
Which two wires go to ac power?
 

AnalogKid

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As above, 13001 is a high voltage NPN.

I think the days of resistors burning short are behind us. I still have some carbon comps for high freq work, but in my experience, spiral cut carbon film and metal film guys burn open.

Care to share the sch?

ak
 

ronsimpson

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With errors! There must be something wrong. F1, C1, C2 why.
1554993281952.png
I need to know where the other power wire connects.
 

ronsimpson

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Most Helpful Member
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I am a little lost on the transistor. The silk screen and the part do not match.
Collector=center
 

ronsimpson

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Most Helpful Member
to battery" are the holes for the screws
Yes, I was trying to say wires connect and go off board.
I am trying to get more information for AnalogKid or Nigel.
Right now I think the burned resistor is not 1meg but more like 10 ohms.
Question: Can the battery be connected backwards? How can there be that much power in the burned resistor?
 

rjenkinsgb

Well-Known Member
Question: Can the battery be connected backwards?
The label on the charger says "Induction output 4V 40mA" (photo in post #14).

I believe the socket for the torch houses a coupling coil, like a typical electric toothbrush charger etc. and the transistor is an oscillator to drive the coil. That's why it does not need isolation from the AC side, as if I'm interpreting it correctly there are no exposed connections.
 

ronsimpson

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Most Helpful Member
I think the transistor and induction coil forms a oscillator.
If so then the burnt resistor is not 1meg ohm. But what?
 

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