i had a problem while designing a circuit in which BT 136TRIAC has to be triggered from a half rectified current of 30 mA at about 6V. Its not getting triggered. Even for this supply my trigger circuit is consuming power as the 4.7k 10W resistor is getting heated up so fast.Suggest me a way to trigger it.
The circuit is about "Solid state auto power off on mains failure".
Even Itried this in ORCAD capture but this didnot work. Can anyone share my pain...
the circuit is available at **broken link removed**
In my opinion the schematic contains an error. The R7 (triac gate series resistor) is too big (270K).
When transistor T1 is open, the 9V voltage is applied to gate, via this resistor, so max current is no more then 9V/270kOhm=0.03mA.
Use a 270 OHM resistor instead, to increase current to 30mA.
This is not a correct design... and many energy dissipated.
Triacs don't like the positive DC trigger, most of case fired only half-wawe - depending of load.
I strongly recommend to use an optotriac for firing (eg MOC3041, it contain zero-cross feature). In PSU use a serial capacitor (100nF X2 type) and a bridge rectifier.
I think that the GROUND symbol in the schematic is just a "cero volt reference" for the circuit.
It is certainly NOT connected to EARTH GROUND
If both "grounds" were connected, not only will trigger any ground fault circuit breaker but will be a dangerous system (and will be an "allways on" switch )
I think the same.
In the schematic ( **broken link removed** ) we can see TWO TERMINALS used only: PH(ase) and N(eutral). The earth ground terminal (PE) is not present in the schematic, because is not used.
In this schematic, the mentioned symbol shows the common neutral trace via triac , and represents, of course, a reference for the circuit, but not earth ground. The well known symbol "earth ground" was not properly used.