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How to make battery backup for circuit?

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now thats clear to me. ^_^
who cause the diode to reversed biassed?

hi,
From the 12V supply when its measured after the diode, it will be 11.3V.

So on the battery diode you have 9V on the Anode and 11.3V on the Cathode.

Thats a reverse voltage on the diode of 11.3 - 9V = 2.3V

As you may know a diode has to have a forward bias voltage of about 0.7V before it conducts.

OK.?:)
 
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hi,
From the 12V supply when its measured after the diode, it will be 11.3V.

So on the battery diode you have 9V on the Anode and 11.3V on the Cathode.

Thats a reverse voltage on the diode of 11.3 - 9V = 2.3V

As you may know a diode has to have a forward bias voltage of about 0.7V before it conducts.

OK.?:)

hehehe thanks a lot sir.
 
Bumping a thread after an hour and a half? That's just tacky.
 
bump bump*

Please dont bump me, I bruise very easily...:)

Set your DVM to current and connect the DVM in series with the output of the two diode cathodes and the input of the voltage regulator.

The DVM will display the current into the reg and the battery. OK.?
 
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