The problem with trying to boost a very low voltage like that is switching losses.
ie: A 0.5V drop across the switching device in a 10V input supply doesn't effect the efficiency as bad as a 0.5V drop across the switching device in a 1V supply would.
You could possibly use the classic joule thief circuit to supply enough voltage to start up one of the standard switching ICs. Once running, the IC could supply it's own source of higher voltage for itself and driving the FET switch.