How to Find Power Factor through e.m.f

Hi !

I need some expert help on this, I've been stuck on this question for ever.

18.6KVA, 3 phase, Y-connected synchronous has synchronous reactance of 2.2 ohms per phase. The generator is connected to a 440V, three phase line. The resistance of the armture is negligible.
Calculate the power factor and the load angle of the generator if the magnitude of the generated e.m.f. is 285V

Heres what I managed to work out

Armature resistance = 0
V line = 440V

V phase = 440/root 3= 254V
s phase=s/3=6.2kVA
IA = 6.2kVA/254V = 24.4 A

Ea = V phase + IA ( Ra+Jxs)
285=254+24.4 angle_theta (j2.2)
285=254+(24.4 x angle_theta) (2.2angle_90)

So I am basically stuck at this point, how do I go on in finding the power factor and the load angle from that?

You have a triangle with sides
285
254
24.4 * 2.2

The shortest side represents a load angle of 90 degrees. You want the angle of the 254 side.

**broken link removed**

I make it about 0.862 and 30.47 degrees.