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vinke said:Why do you need to keep it steady? The LCD isnt working?
Surely the voltage will drop because of the loading effect, you can use a driver to get the 5V you want
Your transistor is an emitter-follower with a voltage loss of about 0.8V. The LEDs are about 3.5V for white ones so the total voltage lost is 4.3V.vinke said:A very simple driver would be to use a general purpose NPN transistor as a switch.from your PIC output connect a 1Kohm resistor in series with the base of the transistor.Connect 5V to the transistor's collector and connect a 330 ohm resistor between the emitter and your LCD.You will have more power to your LCD.
Put a 10 ohm resistor then,you will get 70mA.audioguru said:Your transistor is an emitter-follower with a voltage loss of about 0.8V. The LEDs are about 3.5V for white ones so the total voltage lost is 4.3V.
So only 0.7v is across the 330 ohm current-limiting resistor which limits the current to only 2mA. Way too low.
joe_1 said:V+ of the LED of LCD.