hey i can't understand why a high pass ckt o/p is more than the i/p voltage when the i/p is 10vpp 1khz square wave.ckt uses 1k resistor and 0.1uf capacitor.At the o/p in c.r.o it has shown 12vpp for 10vpp i/p.At t=0 normally o/p should be the i/p
hey i can't understand why a high pass ckt o/p is more than the i/p voltage when the i/p is 10vpp 1khz square wave.ckt uses 1k resistor and 0.1uf capacitor.At the o/p in c.r.o it has shown 12vpp for 10vpp i/p.At t=0 normally o/p should be the i/p
It's because of the droop during the time when the input is flat, due to partial discharging of the capacitor. If you look at the amplitude of the transitons (rising and falling edges), you will see that they are 10V p-p. Make the RC time constant much larger, and the phenomenon will mostly (but not entirely) disappear.
Our OP is talking about a highpass circuit.
I believe we did discuss once on this forum a passive RC lowpass with over 3dB peaking in the frequency domain. It also has peaking in the time domain. I couldn't find it when I searched the forums, but I do have the LTspice simulation on my computer.