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help(design a DC power supply using an IC voltage regulator)

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New Member
i need to get output voltage of -5V. Is circuit correct?

Assume that there is negligible ripple voltage across C1.
VC1(pk) = VI = -10V
Vs(peak) = -10V -0.7V - 0.7V

Therefore the secondary voltage rating of the transformer (in rms):
Vs(rms) = -11.7V/1.414 = -8.27 volts

electrical characteristics
Cout= 1uF , cin =0.33uF , Iout= 350mA, Vin = -10V


Well-Known Member
Most Helpful Member

You need more capacitance on the input. 3000uf should do it and get this
working down to low line too. The transformer secondary should be 10vrms,
or a little higher. It might work with a lower rms voltage too if the equivalent
series resistance of the secondary isnt too high.
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