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i have a equipment which works on 46 to 48 volts dc problem is the power supply i have is 53 volts dc is there any solution which can drop sufficient volts to make my equipment work..
The way to heatsink a 3 amp diode is to use a strip of PC board 5 - 8 cm wide. Cut the copper with a saw to create separate lands and drill holes so that the leads can be soldered to the board. Keep the leads fairly short. Each diode is going to dissipate 2 watts, so keep them apart.
The way to heatsink a 3 amp diode is to use a strip of PC board 5 - 8 cm wide. Cut the copper with a saw to create separate lands and drill holes so that the leads can be soldered to the board. Keep the leads fairly short. Each diode is going to dissipate 2 watts, so keep them apart.
This is fairly good but its not that effecient. The heat from the junction of the diode will go through case, then to lead, then to copper board, then to ambient.
I have found it is fairly pointless helping most of the posters because they either have absolutley no idea what they want and most of the requirements run into a problem that only an engineer can solve and only $500 can pay for.
What is the accuracy of your 53 volt source? Is it adjustable? How much current can it supply?
Assuming that your source is 53.0V and you desire 47.0V at 5.0 amperes, you'll be dissipating up to 30 watts. We need more information such as what is your 'equipment'. Is it a motor, lamp, computer, telecommunications rack?
My equipment is BUC (block up converter) used in satellite communications the power supply is not adjustable actually i need something which i can use b/w supply and BUC to decrease the volts the supply gives 53volts 5amp if the amperes drop this not a problem the equipment i using it can also work on 2 to 3 amperes so if you guys can please help me with this i will be very thankful
Are you also sure that your equipment won't work at 53V? 53V is only a 11% increase from 48V. Post a link to the spec sheet of the equipment you are using.
If the equipment takes 5 amp at 48v, the wattage is 240watt
If the voltage is increased to 53v, the wattage is 292 watt. This is an increase of of more than 20%.
This will overload some devices. It is better to lose 25 watts in regulation than overpower the circuit with 53 watts.
4 x 12v globes in series will get very hot with excess voltage/current.
It may be a motor. Excess voltage may overheat it.
It may be a heating-mat designed for 48v.
I have absolutley no idea what the load is. But the request has been for a stable voltage of 48v and I have suggested the simplest solution is to clamp a number of 20 amp bridges to a heatsink and allow each bridge to drop about 1.4v
request has been for a stable voltage of 48v and I have suggested the simplest solution is to clamp a number of 20 amp bridges to a heatsink and allow each bridge to drop about 1.4v
That's not going to give OP a "stable voltage", that's a voltage subtractor. That will actually decrease the stability of the voltage, expressed as a percent, of an unstable source voltage.
BTW - did you know filament bulbs in series burn out sooner than filament bulbs in parallel?
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