transgalactic
Banned
does it defines inner product..(analisys)
C[0,2]\\
f:[0,2]->c\\
[latex]<f,g>=f(0)\overline{g(0)}+f(1)\overline{g(1)}+f(2)\overline{g(2)}[/latex]
i dont know how to solve the complement.
i tried to prove there easier version without the complement first.
<f,g>=f(0)g(0)+f(1)g(1)+f(2)g(2)\\
A.<g,f>=g(0)f(0)+g(1)f(1)+g(2)f(2)=f(0)g(0)+f(1)g(1)+f(2)g(2)=<f,g>
B.x<f,g>=x(f(0)g(0)+f(1)g(1)+f(2)g(2))=xf(0)g(0)+xf(1)g(1)+xf(2)g(2)=<xf,g>=<f,xg>
C.<x+y,g>=(x(0)+y(0))g(0)+(x(1)+y(1))g(1)+(x(2)+y(2))g(2)=<x,g>+<y,g>
step d:
<x,x>=x(0)x(0)+x(1)x(1)+x(2)x(2)
i dont know how to prove that
<x,x> greater or equal 0
i dont know the values of x
??
C[0,2]\\
f:[0,2]->c\\
[latex]<f,g>=f(0)\overline{g(0)}+f(1)\overline{g(1)}+f(2)\overline{g(2)}[/latex]
i dont know how to solve the complement.
i tried to prove there easier version without the complement first.
<f,g>=f(0)g(0)+f(1)g(1)+f(2)g(2)\\
A.<g,f>=g(0)f(0)+g(1)f(1)+g(2)f(2)=f(0)g(0)+f(1)g(1)+f(2)g(2)=<f,g>
B.x<f,g>=x(f(0)g(0)+f(1)g(1)+f(2)g(2))=xf(0)g(0)+xf(1)g(1)+xf(2)g(2)=<xf,g>=<f,xg>
C.<x+y,g>=(x(0)+y(0))g(0)+(x(1)+y(1))g(1)+(x(2)+y(2))g(2)=<x,g>+<y,g>
step d:
<x,x>=x(0)x(0)+x(1)x(1)+x(2)x(2)
i dont know how to prove that
<x,x> greater or equal 0
i dont know the values of x
??
Last edited: