Hi, I built a pizoelecteric foger and it is working well, but when I saw the curve of pizo it is like this:
And my circuit is this:
Problems:
I don`t know how this circuit works.
What shoud I do to this circuit to reform the slope in sin wave . it seems sin wave but it cut!
I forgot to say, bu406 is realy hot and I need a huge hitsink and a strong fan . I think it related to that curve.
Please use a Spelling checker:
1) oscillator, not osilator
2) piezo, not pizo
3) electric, not electeric
4) fogger, not foger
5) sine wave, not sin wave
6) heatsink, not hitsink.
Your circuit does not show where the piezo is connected. Is it parallel to C1?
Please use a Spelling checker:
1) oscillator, not osilator
2) piezo, not pizo
3) electric, not electeric
4) fogger, not foger
5) sine wave, not sin wave
6) heatsink, not hitsink.
Your circuit does not show where the piezo is connected. Is it parallel to C1?
Then if the waveform is a sinewave at 129Vp-p then its RMS voltage is 45.6V.
Is the power supply current 1A? Then the total power is 45.6V x 1A= 45.6W and the Mosfet dissipates half which is 22.8W so it needs a pretty big heatsink.
How is a Piezo element providing a DC path to the base of the transistor? Do you have a data sheet for it? I have never seen a piezo that doesn't look like a capacitor when measured with an Ohmmeter. Try it.
I don't understand how this oscillates. I wonder if it is a negative resistance oscillator, with the negative resistance being provided by collector-emitter avalanche.
The average voltage (-6V) and the flat top on the waveform leads me to suspect that the base-emitter is also breaking down.
I wouldn't be surprised if the transistor has a short, painful life.
So, is that fog in the picture from the piezo element, or steam from the hot transistor?
EDIT: I just looked at the datasheet of BU406. Vceo is 200V, so that pretty much shoots down my avalanche theory.
Then if the waveform is a sinewave at 129Vp-p then its RMS voltage is 45.6V.
Is the power supply current 1A? Then the total power is 45.6V x 1A= 45.6W and the Mosfet dissipates half which is 22.8W so it needs a pretty big heatsink.
Yes the power of my circuit is 45W ,but somenoe else built this circuit from this schematic and the transistor is really cool.!
If we create a sine wave on a transistor in theory we will have 0 loss power on it! but if the wave were square we would have some losses on transistor or switch part of circuit.
How is a Piezo element providing a DC path to the base of the transistor? Do you have a data sheet for it? I have never seen a piezo that doesn't look like a capacitor when measured with an Ohmmeter. Try it.
If we contact a piezo to dc voltage it will act az a short circuit for a few mili seconds ( it related to piezo frequency) and after while it goes to open circuit. and in this schematic we will have a ac voltage .
If we contact a piezo to dc voltage it will act az a short circuit for a few mili seconds ( it related to piezo frequency) and after while it goes to open circuit. and in this schematic we will have a ac voltage .
the piezo acts at first as a capacitor, that's what gets the oscillation started. after that it acts as a series resonant circuit, and since there's a 180 degree phase shift at resonance, provides positive feedback to the base of the transistor.
the piezo acts at first as a capacitor, that's what gets the oscillation started. after that it acts as a series resonant circuit, and since there's a 180 degree phase shift at resonance, provides positive feedback to the base of the transistor.
The circuit you posted is NOT a Pierce Crystal Oscillator because it is missing a few important parts.
Besides, a crystal oscillator has very low power in the crystal. You need a circuit that produces very high power in a piezo transducer.